[Java]프로그래머스 Lv. 0 잘라서 배열로 저장하기

https://school.programmers.co.kr/learn/courses/30/lessons/120913

프로그래머스

나의 풀이

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

class Solution {
    public String[] solution(String my_str, int n) {
        List<String> answer = new ArrayList<>();
        for (int i = 0; i < (my_str.length() / n); i++) {
            answer.add(my_str.substring((n * i), (n * (i + 1))));
        }
        if (my_str.length() % n != 0) {
            answer.add(my_str.substring( (my_str.length() / n) * n));
        }
        return answer.toArray(new String[0]);
    }
}

다른 풀이

import java.util.*;
import java.util.stream.IntStream;

class Solution {
    public String[] solution(String myStr, int n) {
        return IntStream.range(0, myStr.length() / n + (myStr.length() % n > 0 ? 1 : 0))
                .mapToObj(i -> i == myStr.length() / n ? myStr.substring(i * n) : myStr.substring(i * n, (i + 1) * n))
                .toArray(String[]::new);
    }
}

class Solution {
    public String[] solution(String my_str, int n) {
        int resultCnt = (my_str.length() + n - 1) / n;
        String[] answer = new String[resultCnt];

        for (int i = 0; i < resultCnt; i++) {
            int start = n * i;
            int end = start + n >= my_str.length()? my_str.length(): start + n;
            answer[i] = my_str.substring(start, end);
        }

        return answer;
    }
}